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(Created page with "'''Answer: D''' <math>e_{[61]}=e_{[61]: 37}+{ }_{3} p_{[61]}\left(e_{64}\right)</math> <math>p_{[61]}=0.90</math>, <math>{ }_{2} p_{[61]}=0.9(0.88)=0.792</math>, <math>{ }_{3} p_{[61]}=0.792(0.86)=0.68112</math> <math>e_{[61]: 3]}=\sum_{k=1}^{3}{ }_{k} p_{[61]}=0.9+0.792+0.68112=2.37312</math> <math>e_{[61]}=2.37312+0.68112 e_{64}=2.37312+0.68112(5.10)=5.847</math>") |
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<math>e_{[61]}=2.37312+0.68112 e_{64}=2.37312+0.68112(5.10)=5.847</math> | <math>e_{[61]}=2.37312+0.68112 e_{64}=2.37312+0.68112(5.10)=5.847</math> | ||
{{soacopyright|2024}} | |||
Revision as of 02:33, 18 January 2024
Answer: D
[math]e_{[61]}=e_{[61]: 37}+{ }_{3} p_{[61]}\left(e_{64}\right)[/math]
[math]p_{[61]}=0.90[/math],
[math]{ }_{2} p_{[61]}=0.9(0.88)=0.792[/math],
[math]{ }_{3} p_{[61]}=0.792(0.86)=0.68112[/math]
[math]e_{[61]: 3]}=\sum_{k=1}^{3}{ }_{k} p_{[61]}=0.9+0.792+0.68112=2.37312[/math]
[math]e_{[61]}=2.37312+0.68112 e_{64}=2.37312+0.68112(5.10)=5.847[/math]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.