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<math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math> | <math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math> | ||
{{soacopyright|2024}} | |||
{{soacopyright|2024}} | {{soacopyright|2024}} | ||
Revision as of 02:34, 18 January 2024
Answer: B
[math]{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298[/math]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.