exercise:Cee9df3ed8: Difference between revisions
(Created page with "An insurer is modelling time to death of lives insured at age <math>x</math> using the Kaplan-Meier estimator. You are given the following information. (i) There were 100 policies in force at time 0 (ii) There were no new policies entering the study (iii) At time 10.0, immediately after a death, there were 50 policies remaining in force (iv) The Kaplan-Meier estimate of the survival function for death at time 10 is <math>\hat{S}(10.0)=0.92</math> (v) The next death...") |
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<ul class="mw-excansopts"><li> 0.897</li><li> 0.903</li><li> 0.909</li><li> 0.910</li><li> 0.920</li></ul> | <ul class="mw-excansopts"><li> 0.897</li><li> 0.903</li><li> 0.909</li><li> 0.910</li><li> 0.920</li></ul> | ||
{{soacopyright|2024}} | |||
Latest revision as of 02:40, 18 January 2024
An insurer is modelling time to death of lives insured at age [math]x[/math] using the Kaplan-Meier estimator. You are given the following information.
(i) There were 100 policies in force at time 0
(ii) There were no new policies entering the study
(iii) At time 10.0, immediately after a death, there were 50 policies remaining in force
(iv) The Kaplan-Meier estimate of the survival function for death at time 10 is [math]\hat{S}(10.0)=0.92[/math]
(v) The next death after time 10.0 occurred when there was one death at time 10.8
(vi) During the period from time 10.0 to time 10.8 , a total of 10 policies terminated for reasons other than death
Calculate [math]\hat{S}(10.8)[/math], the Kaplan-Meier estimate of the survival function [math]S(10.8)[/math].
- 0.897
- 0.903
- 0.909
- 0.910
- 0.920
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.