exercise:E6f17799c6: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\indexmark}[1]{#1\markboth{#1}{#1}} \newcommand{\red}[1]{\textcolor{red}{#1}} \newcommand{\NOTE}[1]{$^{\textcolor{red}\clubsuit}$\marginpar{\setstretch{0.5}$^{\scriptscriptstyle\textcolor{red}\clubsuit}$\textcolor{blue}{\bf\tiny #1}}} \newcommand\xoverline[2][0.75]{% \sbox{\myboxA}{$\m@th#2$}% \setbox\myboxB\null% Phantom box \ht\myboxB=\ht\myboxA% \dp\myboxB=\dp\myboxA% \wd\myboxB=#1\wd\myboxA% Scale phantom...")
 
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Let <math>\Bbar_1(0)</math> denote the unit ball of <math>\mathbb{R}^d</math>.
Let <math>\Bbar_1(0)</math> denote the unit ball of <math>\mathbb{R}^d</math>.
<ul style="list-style-type:lower-roman"><li> Use [[#LEM-9-2 |Lemma]] to compute <math>\lambda^d(\Bbar_1(0))</math> for <math>d=1,\dots,10</math>.
<ul style="list-style-type:lower-roman"><li> Use [[#LEM-9-2 |Lemma]] to compute <math>\lambda^d(\Bbar_1(0))</math> for <math>d=1,\dots,10</math>.

Revision as of 01:44, 1 June 2024

[math] \newcommand{\smallfrac}[2]{\frac{#1}{#2}} \newcommand{\medfrac}[2]{\frac{#1}{#2}} \newcommand{\textfrac}[2]{\frac{#1}{#2}} \newcommand{\tr}{\operatorname{tr}} \newcommand{\e}{\operatorname{e}} \newcommand{\B}{\operatorname{B}} \newcommand{\Bbar}{\overline{\operatorname{B}}} \newcommand{\pr}{\operatorname{pr}} \newcommand{\dd}{\operatorname{d}\hspace{-1pt}} \newcommand{\E}{\operatorname{E}} \newcommand{\V}{\operatorname{V}} \newcommand{\Cov}{\operatorname{Cov}} \newcommand{\Bigsum}[2]{\mathop{\textstyle\sum}_{#1}^{#2}} \newcommand{\ran}{\operatorname{ran}} \newcommand{\card}{\#} \newcommand{\mathds}{\mathbb}[/math]


Let [math]\Bbar_1(0)[/math] denote the unit ball of [math]\mathbb{R}^d[/math].

  • Use Lemma to compute [math]\lambda^d(\Bbar_1(0))[/math] for [math]d=1,\dots,10[/math].
  • Compute [math]\lim_{d\rightarrow\infty}\lambda^d(\Bbar_1(0))[/math].
  • Show that [math]\lambda^d(\Bbar_1(0))=\medfrac{\pi^{d/2}}{\Gamma(d/2+1)}[/math] holds, where [math]\Gamma\colon(0,\infty)\rightarrow\mathbb{R}[/math] denotes the Gamma function.