exercise:4467c24225: Difference between revisions
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The equation <math>(x^2 + y^2)^2 = 2(x^2 - y^2)</math> | The equation <math>(x^2 + y^2)^2 = 2(x^2 - y^2)</math> | ||
implicitly defines a differentiable function <math>f(x)</math> whose graph passes | implicitly defines a differentiable function <math>f(x)</math> whose graph passes | ||
through the point <math>\left( \frac{\sqrt3}{2}, \frac12\right)</math>. | through the point <math>\left( \frac{\sqrt3}{2}, \frac12\right)</math>. | ||
Compute <math>f^\prime \left( \frac{\sqrt3}2 \right)</math>. | Compute <math>f^\prime \left( \frac{\sqrt3}2 \right)</math>. | ||
Latest revision as of 23:33, 22 November 2024
[math]
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[/math]
The equation [math](x^2 + y^2)^2 = 2(x^2 - y^2)[/math] implicitly defines a differentiable function [math]f(x)[/math] whose graph passes through the point [math]\left( \frac{\sqrt3}{2}, \frac12\right)[/math]. Compute [math]f^\prime \left( \frac{\sqrt3}2 \right)[/math].