excans:Edab1efc0b: Difference between revisions
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(Created page with "<math>X(1+i / 2)^{16}-X(1+i / 2)^{15}=2 X(1+8 i)-2 X(1+7.5 i)</math> so <math>(1+i / 2)^{15} i / 2=2(.5) i</math> so <math>(1+i / 2)^{15}=2</math> so <math>i / 2=2^{1 / 15}-1=.04729</math> so <math>i=.09458</math>. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}") |
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'''Solution: A''' | |||
<math>X(1+i / 2)^{16}-X(1+i / 2)^{15}=2 X(1+8 i)-2 X(1+7.5 i)</math> so <math>(1+i / 2)^{15} i / 2=2(.5) i</math> so <math>(1+i / 2)^{15}=2</math> so <math>i / 2=2^{1 / 15}-1=.04729</math> so <math>i=.09458</math>. | <math>X(1+i / 2)^{16}-X(1+i / 2)^{15}=2 X(1+8 i)-2 X(1+7.5 i)</math> so <math>(1+i / 2)^{15} i / 2=2(.5) i</math> so <math>(1+i / 2)^{15}=2</math> so <math>i / 2=2^{1 / 15}-1=.04729</math> so <math>i=.09458</math>. | ||
Latest revision as of 17:20, 26 November 2023
Solution: A
[math]X(1+i / 2)^{16}-X(1+i / 2)^{15}=2 X(1+8 i)-2 X(1+7.5 i)[/math] so [math](1+i / 2)^{15} i / 2=2(.5) i[/math] so [math](1+i / 2)^{15}=2[/math] so [math]i / 2=2^{1 / 15}-1=.04729[/math] so [math]i=.09458[/math].
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.