exercise:A82a34788d: Difference between revisions
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If <math>X</math> has a normal distribution with mean 2 and standard deviation 1.5, determine <math>\operatorname{P}[X^2 - X -2 > 0 ] </math>. | If <math>X</math> has a normal distribution with mean 2 and standard deviation 1.5, determine <math>\operatorname{P}[X^2 - X -2 > 0 ] </math>. | ||
< | <ul class="mw-excansopts"> | ||
<li>0</li> | <li>0</li> | ||
<li>0. | <li>0.477</li> | ||
<li>0.5</li> | <li>0.5</li> | ||
<li>0. | <li>0.523</li> | ||
<li>1</li> | <li>1</li> | ||
</ | </ul> | ||
Latest revision as of 19:24, 3 July 2024
If [math]X[/math] has a normal distribution with mean 2 and standard deviation 1.5, determine [math]\operatorname{P}[X^2 - X -2 \gt 0 ] [/math].
- 0
- 0.477
- 0.5
- 0.523
- 1