excans:3e5e466d03: Difference between revisions
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(Created page with "Answer: B <math display="block"> \stackrel{\circ}{e}_{[58]+2}=e_{[58]+2}+0.5 </math> <math display = "block">e_{[58]+2}=p_{[58]+2}\left(1+e_{61}\right)=p_{[58]+2}\left[1+\frac{e_{60}}{p_{60}}-1\right]</math> <math display = "block">=\frac{l_{61}}{l_{[58]+2}} \times \frac{e_{60}}{p_{60}}=\frac{2210}{3548} \times \frac{1}{(2210 / 3904)}=\frac{3904}{3549}=1.100338</math> <math display = "block">\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6</math>") |
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Answer: B | '''Answer: B''' | ||
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<math display = "block">\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6</math> | <math display = "block">\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6</math> | ||
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Latest revision as of 02:34, 18 January 2024
Answer: B
[[math]]
\stackrel{\circ}{e}_{[58]+2}=e_{[58]+2}+0.5
[[/math]]
[[math]]e_{[58]+2}=p_{[58]+2}\left(1+e_{61}\right)=p_{[58]+2}\left[1+\frac{e_{60}}{p_{60}}-1\right][[/math]]
[[math]]=\frac{l_{61}}{l_{[58]+2}} \times \frac{e_{60}}{p_{60}}=\frac{2210}{3548} \times \frac{1}{(2210 / 3904)}=\frac{3904}{3549}=1.100338[[/math]]
[[math]]\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6[[/math]]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.