exercise:1f87b519f4: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> For each of the distributions (a) through (d) of Exercise \ref{exer 10.1.1} calculate the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their definition, and verify that <math>h(1) = 1</math>, <math>h'(1) = \mu...")
 
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<div class="d-none"><math>
For each of the distributions (a) through (d) of [[exercise:531abde51b|Exercise]] calculate the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their definition, and verify that <math>h(1) = 1</math>, <math>h'(1) = \mu_1</math>, and <math>h''(1) = \mu_2 -
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> For each of the distributions (a) through (d) of Exercise \ref{exer
10.1.1} calculate the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their
definition, and verify that <math>h(1) = 1</math>, <math>h'(1) = \mu_1</math>, and <math>h''(1) = \mu_2 -
\mu_1</math>.
\mu_1</math>.

Latest revision as of 23:42, 14 June 2024

For each of the distributions (a) through (d) of Exercise calculate the first and second moments, [math]\mu_1[/math] and [math]\mu_2[/math], directly from their definition, and verify that [math]h(1) = 1[/math], [math]h'(1) = \mu_1[/math], and [math]h''(1) = \mu_2 - \mu_1[/math].