excans:0c52b34335: Difference between revisions
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(Created page with "'''Solution: C''' The time diagram is {| class="table table-borderless" |- | Time || 0 || 1 || 2 || 3 || 4 || 5 |- | Deposit || || 1000 || 1000 || 1000 ||1000 || 1000 |- | CumDeposit || || 1000 || 2000 || 3000 || 4000 || 5000 |- | Interest || || || 100 || 200 ||300 ||400 |} Hence the accumulated amount is <math display="block"> 5000+100(I s)_{\overline{4} \mid .08}=5000+100 \frac{\ddot{s}_{\overline{4} \mid .08}-4}{.08}=5000+100 \frac{4.866601-4}{.08}=6083.25 </math>...") |
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The time diagram is | The time diagram is | ||
Latest revision as of 21:45, 29 November 2023
Solution: C
The time diagram is
| Time | 0 | 1 | 2 | 3 | 4 | 5 |
| Deposit | 1000 | 1000 | 1000 | 1000 | 1000 | |
| CumDeposit | 1000 | 2000 | 3000 | 4000 | 5000 | |
| Interest | 100 | 200 | 300 | 400 |
Hence the accumulated amount is
[[math]]
5000+100(I s)_{\overline{4} \mid .08}=5000+100 \frac{\ddot{s}_{\overline{4} \mid .08}-4}{.08}=5000+100 \frac{4.866601-4}{.08}=6083.25
[[/math]]
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.