exercise:99e9f3696b: Difference between revisions
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(Created page with "You are given the following estimated survival properties and risk sets determined using the Kaplan-Meier method. {| class="table table-bordered" ! <math>j</math> !! <math>t_{(j)}</math> !! <math>r_{j}</math> !! <math>\hat{p}_{j}</math> |- | 1 || 17.2 || 29 || 0.9655 |- | 2 || 22.1 || 27 || 0.9259 |- | 3 || 32.7 || 24 || 0.9583 |- | 4 || 45.0 || 20 || 0.9500 |} Calculate the standard deviation of <math>\hat{S}(25)</math> using Greenwood's formula. <ul class="mw-excans...") |
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<ul class="mw-excansopts"><li> 0.0543</li><li> 0.0556</li><li> 0.0579</li><li> 0.0604</li><li> 0.0626</li></ul> | <ul class="mw-excansopts"><li> 0.0543</li><li> 0.0556</li><li> 0.0579</li><li> 0.0604</li><li> 0.0626</li></ul> | ||
{{soacopyright|2024}} | |||
Latest revision as of 02:40, 18 January 2024
You are given the following estimated survival properties and risk sets determined using the Kaplan-Meier method.
| [math]j[/math] | [math]t_{(j)}[/math] | [math]r_{j}[/math] | [math]\hat{p}_{j}[/math] |
|---|---|---|---|
| 1 | 17.2 | 29 | 0.9655 |
| 2 | 22.1 | 27 | 0.9259 |
| 3 | 32.7 | 24 | 0.9583 |
| 4 | 45.0 | 20 | 0.9500 |
Calculate the standard deviation of [math]\hat{S}(25)[/math] using Greenwood's formula.
- 0.0543
- 0.0556
- 0.0579
- 0.0604
- 0.0626
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.