excans:3e5e466d03: Difference between revisions
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<math display = "block">\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6</math> | <math display = "block">\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6</math> | ||
{{soacopyright|2024}} | |||
{{soacopyright|2024}} | {{soacopyright|2024}} | ||
Revision as of 02:34, 18 January 2024
Answer: B
[[math]]
\stackrel{\circ}{e}_{[58]+2}=e_{[58]+2}+0.5
[[/math]]
[[math]]e_{[58]+2}=p_{[58]+2}\left(1+e_{61}\right)=p_{[58]+2}\left[1+\frac{e_{60}}{p_{60}}-1\right][[/math]]
[[math]]=\frac{l_{61}}{l_{[58]+2}} \times \frac{e_{60}}{p_{60}}=\frac{2210}{3548} \times \frac{1}{(2210 / 3904)}=\frac{3904}{3549}=1.100338[[/math]]
[[math]]\stackrel{\circ}{e}_{[58]+2}=1.100338+0.5=1.6[[/math]]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.