excans:9cf0d90d18: Difference between revisions
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<math>\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56</math> | <math>\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56</math> | ||
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{{soacopyright|2024}} | {{soacopyright|2024}} | ||
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Revision as of 02:34, 18 January 2024
Answer: D
[math]\hat{S}(30)=\frac{100-10-14-16}{100}=0.60, \quad \hat{S}(40)=\frac{100-10-14-16-20}{100}=0.40[/math]
Use linear interpolation to find [math]\hat{S}(32)[/math]
[math]\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56[/math]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.