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<math>\Rightarrow 95 \% \mathrm{CI}</math> is approximately <math>(0.8 \pm 1.96(0.01265))=(0.775,0.825)</math> | <math>\Rightarrow 95 \% \mathrm{CI}</math> is approximately <math>(0.8 \pm 1.96(0.01265))=(0.775,0.825)</math> | ||
{{soacopyright|2024}} | |||
{{soacopyright|2024}} | {{soacopyright|2024}} | ||
{{soacopyright|2024}} | {{soacopyright|2024}} | ||
Revision as of 02:34, 18 January 2024
Answer: D
[math]\hat{S}(1)=0.8[/math]
[math]\operatorname{Var}[S(1)]=\frac{S(1)(1-S(1)}{n} \approx \frac{(0.8)(0.2)}{1000}=0.01265^{2}[/math]
[math]\Rightarrow 95 \% \mathrm{CI}[/math] is approximately [math](0.8 \pm 1.96(0.01265))=(0.775,0.825)[/math]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.