excans:9cf0d90d18: Difference between revisions
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<math>\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56</math> | <math>\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56</math> | ||
{{soacopyright|2024}} | {{soacopyright|2024}} | ||
Latest revision as of 02:37, 18 January 2024
Answer: D
[math]\hat{S}(30)=\frac{100-10-14-16}{100}=0.60, \quad \hat{S}(40)=\frac{100-10-14-16-20}{100}=0.40[/math]
Use linear interpolation to find [math]\hat{S}(32)[/math]
[math]\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56[/math]
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.