exercise:F0cf895cea: Difference between revisions
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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> A piece of rope is made up of 100 strands. Assume that the breaking strength of the rope is the sum of the breaking strengths of the individual strands. Assume further that this sum may be considered to be the sum of an independent trials proce...") |
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A piece of rope is made up of 100 strands. Assume that the breaking | |||
strength of the rope is the sum of the breaking strengths of the individual | strength of the rope is the sum of the breaking strengths of the individual | ||
strands. Assume further that this sum may be considered to be the sum of an | strands. Assume further that this sum may be considered to be the sum of an | ||
| Line 11: | Line 5: | ||
10 pounds and standard deviation 1. Find the approximate probability that the | 10 pounds and standard deviation 1. Find the approximate probability that the | ||
rope will support a weight | rope will support a weight | ||
<ul><li> of 1000 pounds. | <ul style="list-style-type:lower-alpha"><li> of 1000 pounds. | ||
</li> | </li> | ||
<li> of 970 pounds. | <li> of 970 pounds. | ||
</li> | </li> | ||
</ul> | </ul> | ||
Latest revision as of 00:02, 15 June 2024
A piece of rope is made up of 100 strands. Assume that the breaking strength of the rope is the sum of the breaking strengths of the individual strands. Assume further that this sum may be considered to be the sum of an independent trials process with 100 experiments each having expected value of 10 pounds and standard deviation 1. Find the approximate probability that the rope will support a weight
- of 1000 pounds.
- of 970 pounds.