exercise:E61d76b91c: Difference between revisions
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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> We have seen that if the generating function for the offspring of a single parent is <math>f(z)</math>, then the generating function for the number of offspring after two generations is given by <math>h(z) = f(f(z))</math>. Explain how this follo...") |
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We have seen that if the generating function for the offspring of a single parent is <math>f(z)</math>, then the generating function for the number of | |||
single parent is <math>f(z)</math>, then the generating function for the number of | |||
offspring after two generations is given by <math>h(z) = f(f(z))</math>. Explain how this | offspring after two generations is given by <math>h(z) = f(f(z))</math>. Explain how this | ||
follows from the result of | follows from the result of [[exercise:6eeb09869c |Exercise]]. |
Latest revision as of 23:50, 14 June 2024
We have seen that if the generating function for the offspring of a single parent is [math]f(z)[/math], then the generating function for the number of offspring after two generations is given by [math]h(z) = f(f(z))[/math]. Explain how this follows from the result of Exercise.