exercise:1192305405: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> <math>X</math> is a random variable with <math>E(X) = 100</math> and <math>V(X) = 15</math>. Find <ul><li> <math>E(X^2)</math>. </li> <li> <math>E(3X + 10)</math>. </li> <li> <math>E(-X)</math>. </li> <li> <math>V(-X)</math>. </li> <li> <math>D(-...")
 
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<div class="d-none"><math>
<math>X</math> is a random variable with <math>E(X) = 100</math> and <math>V(X) = 15</math>.  
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> <math>X</math> is a random variable with <math>E(X) = 100</math> and <math>V(X) = 15</math>.  
Find
Find
<ul><li> <math>E(X^2)</math>.
<ul style="list-style-type:lower-alpha"><li> <math>E(X^2)</math>.
</li>
</li>
<li> <math>E(3X + 10)</math>.
<li> <math>E(3X + 10)</math>.

Latest revision as of 20:59, 14 June 2024

[math]X[/math] is a random variable with [math]E(X) = 100[/math] and [math]V(X) = 15[/math]. Find

  • [math]E(X^2)[/math].
  • [math]E(3X + 10)[/math].
  • [math]E(-X)[/math].
  • [math]V(-X)[/math].
  • [math]D(-X)[/math].