exercise:8c7814d1ff: Difference between revisions
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</math></div> | </math></div> | ||
Assume that <math>0 < c < a</math>. | Assume that <math>0 < c < a</math>. | ||
<ul style{{=}}"list-style-type:lower-alpha" | <ul style{{=}}"list-style-type:lower-alpha"> | ||
<li> | <li>Find the distance between <math>(x,y)</math> and <math>(-c,0)</math>.</li> | ||
Find the distance between <math>(x,y)</math> and <math>(-c,0)</math>.</li> | <li>Find the distance between <math>(x,y)</math> and the line <math>x = -\frac{a^2}c</math>.</li> | ||
<li> | |||
Find the distance between <math>(x,y)</math> and the line <math>x = -\frac{a^2}c</math>.</li> | |||
<li>Find the locus of points <math>(x,y)</math> such that the ratio between | <li>Find the locus of points <math>(x,y)</math> such that the ratio between | ||
the distance in | the distance in (a) and the distance in (b) | ||
is a constant <math>\frac ca</math>.</li> | is a constant <math>\frac ca</math>.</li> | ||
</ul> | </ul> | ||
Latest revision as of 00:48, 23 November 2024
[math]
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[/math]
Assume that [math]0 \lt c \lt a[/math].
- Find the distance between [math](x,y)[/math] and [math](-c,0)[/math].
- Find the distance between [math](x,y)[/math] and the line [math]x = -\frac{a^2}c[/math].
- Find the locus of points [math](x,y)[/math] such that the ratio between the distance in (a) and the distance in (b) is a constant [math]\frac ca[/math].