exercise:A7a1c3d027: Difference between revisions
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Consider a point <math>(x_1,y_1)</math> on the graph of | Consider a point <math>(x_1,y_1)</math> on the graph of | ||
<math>b^2x^2 + a^2y^2 = a^2b^2</math>. | <math>b^2x^2 + a^2y^2 = a^2b^2</math>. | ||
<ul style{{=}}"list-style-type:lower-alpha" | <ul style{{=}}"list-style-type:lower-alpha"> | ||
<li> | <li>Find the slope of the tangent to the graph at <math>(x_1,y_1)</math>.</li> | ||
Find the slope of the tangent to the graph at <math>(x_1,y_1)</math>. | <li>Write an equation of the tangent line in (a).</li> | ||
<li>Write an equation of the tangent line in | |||
<li>Show that <math>b^2xx_1 + a^2yy_1 = a^2b^2</math> | <li>Show that <math>b^2xx_1 + a^2yy_1 = a^2b^2</math> | ||
is an equation of the tangent line.</li> | is an equation of the tangent line.</li> | ||
</ul> | </ul> | ||
Latest revision as of 00:49, 23 November 2024
[math]
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[/math]
Consider a point [math](x_1,y_1)[/math] on the graph of [math]b^2x^2 + a^2y^2 = a^2b^2[/math].
- Find the slope of the tangent to the graph at [math](x_1,y_1)[/math].
- Write an equation of the tangent line in (a).
- Show that [math]b^2xx_1 + a^2yy_1 = a^2b^2[/math] is an equation of the tangent line.