excans:Cfe6e6e7cf: Difference between revisions
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(Created page with "For <math>\mathrm{Q}</math> the accumulated value is <math>Xs_{25 \mid 0.09}=84.7009 X</math>. For <math>\mathrm{R}</math> the accumulated value is <math display = "block">100(25)+9(Is)_{\overline{24}|0.08}=2500+9 \frac{\ddot{s}_{\overline{24} | 0.08}-24}{0.08}=2500+9 \frac{72.1059-24}{0.08}=7911.91</math>. Then <math>X=7911.91 / 84.7009=93.41</math>. {{soacopyright | 2023 }}") |
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'''Solution: D''' | |||
For <math>\mathrm{Q}</math> the accumulated value is <math>Xs_{25 \mid 0.09}=84.7009 X</math>. For <math>\mathrm{R}</math> the accumulated value is <math display = "block">100(25)+9(Is)_{\overline{24}|0.08}=2500+9 \frac{\ddot{s}_{\overline{24} | 0.08}-24}{0.08}=2500+9 \frac{72.1059-24}{0.08}=7911.91</math>. Then <math>X=7911.91 / 84.7009=93.41</math>. | For <math>\mathrm{Q}</math> the accumulated value is <math>Xs_{25 \mid 0.09}=84.7009 X</math>. For <math>\mathrm{R}</math> the accumulated value is <math display = "block">100(25)+9(Is)_{\overline{24}|0.08}=2500+9 \frac{\ddot{s}_{\overline{24} | 0.08}-24}{0.08}=2500+9 \frac{72.1059-24}{0.08}=7911.91</math>. Then <math>X=7911.91 / 84.7009=93.41</math>. | ||
{{soacopyright | 2023 }} | {{soacopyright | 2023 }} |
Latest revision as of 11:51, 18 November 2023
Solution: D
For [math]\mathrm{Q}[/math] the accumulated value is [math]Xs_{25 \mid 0.09}=84.7009 X[/math]. For [math]\mathrm{R}[/math] the accumulated value is
[[math]]100(25)+9(Is)_{\overline{24}|0.08}=2500+9 \frac{\ddot{s}_{\overline{24} | 0.08}-24}{0.08}=2500+9 \frac{72.1059-24}{0.08}=7911.91[[/math]]
. Then [math]X=7911.91 / 84.7009=93.41[/math].