exercise:802078ad82: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> Prove that the probability of exactly <math>n</math> heads in <math>2n</math> tosses of a fair coin is given by the product of the odd numbers up to <math>2n - 1</math> divided by the product of the even numbers up to <math>2n</math>.")
 
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<div class="d-none"><math>
Prove that the probability of exactly <math>n</math> heads in <math>2n</math> tosses of a fair coin is given by the product of the odd numbers up to <math>2n - 1</math> divided by the product of the even numbers up to <math>2n</math>.
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> Prove that the probability of exactly <math>n</math> heads in
<math>2n</math> tosses of a fair coin is given by the product of the odd numbers up to <math>2n - 1</math>
divided by the product of the even numbers up to <math>2n</math>.

Latest revision as of 00:13, 13 June 2024

Prove that the probability of exactly [math]n[/math] heads in [math]2n[/math] tosses of a fair coin is given by the product of the odd numbers up to [math]2n - 1[/math] divided by the product of the even numbers up to [math]2n[/math].