Revision as of 13:50, 14 May 2023 by Admin
Exercise
ABy Admin
May 14'23
Answer
Key: B
For Product X: aggregate losses have mean 10*20 = 200 and variance 10*25 + 400*9 = 3850.
For Product Y: aggregate losses have mean 2*50 = 100 and variance 2*100 + 2500 = 2700.
Because Product X and Product Y are independent, total aggregate losses, S, have mean 300 and variance 6550.
Using the normal approximation, we have:
[[math]]
\operatorname{P}( S \gt 400) = \operatorname{P} \left( \frac{S-300}{\sqrt{6550}} \gt \frac{400-300}{\sqrt{6550}} \right)= \operatorname{P}(Z \gt 1.24 ) = 0.11
[[/math]]