Revision as of 02:36, 9 June 2024 by Bot (Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> In the text, it was shown that if <math>q < p</math>, there is a positive probability that a gambler, starting with a stake of 0 dollars, will never return to the origin. Thus, we will now assume that <math>q \ge p</math>. Using Exercise exe...")
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Jun 09'24

Exercise

[math] \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}[/math]

In the text, it was shown that if [math]q \lt p[/math], there is a positive probability

that a gambler, starting with a stake of 0 dollars, will never return to the origin. Thus, we will now assume that [math]q \ge p[/math]. Using Exercise Exercise, show that if a gambler starts with a stake of 0 dollars, then the expected number of times her stake equals [math]M[/math] before returning to 0 equals [math](p/q)^M[/math], if [math]q \gt p[/math] and 1, if [math]q = p[/math]. (We quote from Feller: “The truly amazing implications of this result appear best in the language of fair games. A perfect coin is tossed until the first equalization of the accumulated numbers of heads and tails. The gambler receives one penny for every time that the accumulated number of heads exceeds the accumulated number of tails by [math]m[/math]. The `fair entrance fee' equals 1 independent of [math]m[/math].”)