Revision as of 13:12, 14 May 2023 by Admin (Created page with "The repair costs for boats in a marina have the following characteristics: {| class = "table table-bordered" |Boat type | Number of boats | Probability that repair is needed...")
ABy Admin
May 14'23
Exercise
The repair costs for boats in a marina have the following characteristics:
Boat type | Number of boats | Probability that repair is needed | Mean of repair cost given a repair | Variance of repair cost given a repair |
Power boats | 100 | 0.3 | 300 | 10,000 |
Sailboats | 300 | 0.1 | 1000 | 400,000 |
Luxury yachts | 50 | 0.6 | 5000 | 2,000,000 |
At most one repair is required per boat each year. Repair incidence and cost are mutually independent. The marina budgets an amount, [math]Y[/math], equal to the aggregate mean repair costs plus the standard deviation of the aggregate repair costs.
Calculate [math]Y[/math].
ABy Admin
May 14'23
Key: B
The number of repairs for each boat type has a binomial distribution. For power boats:
[[math]]
\begin{aligned}
&\operatorname{E}[ S ] = 100(0.3)(300) = 9, 000, \\
&\operatorname{E}[ S ] = 100(0.3)10, 000) + 100(0.3)(0.7)(300 2 ) = 2,190, 000
\end{aligned}
[[/math]]
For sail boats:
[[math]]
\begin{aligned}
&\operatorname{E}[ S ] = 300(0.1)(1, 000) = 30, 000, \\
&\operatorname{E}[ S ] = 300(0.1)(400, 000) + 300(0.1)(0.9)(1, 0002 ) = 39, 000, 000
\end{aligned}
[[/math]]
For luxury yachts:
[[math]]
\begin{aligned}
&\operatorname{E}[ S ] = 50(0.6)(5, 000) = 150, 000, \\
&\operatorname{E}[ S ] = 50(0.6)(0.4)(2, 000, 000) + 50(0.6)(0.4)(5, 0002 ) = 360, 000, 000
\end{aligned}
[[/math]]
The sums are 189,000 expected and a variance of 401,190,000 for a standard deviation of 20,030. The mean plus standard deviation is 209,030.