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Exercise


ABy Admin
May 14'23

Answer

Key: B

For Product X: aggregate losses have mean 10*20 = 200 and variance 10*25 + 400*9 = 3850.

For Product Y: aggregate losses have mean 2*50 = 100 and variance 2*100 + 2500 = 2700.

Because Product X and Product Y are independent, total aggregate losses, S, have mean 300 and variance 6550.

Using the normal approximation, we have:

[[math]] P( S \gt 400) = P \left( \frac{S-300}{\sqrt{6550}} \gt \frac{400-300}{\sqrt{6550}} \right)= P(Z \gt 1.24 ) = 0.11 [[/math]]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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