Revision as of 11:53, 18 November 2023 by Admin (Created page with "'''Solution: A''' The 3-year interest rate is <math>1.07^3-1=0.225043</math> Then, <math display = "block"> 735=X\ddot{a}_{\overline{\infty}|0.225043}=X\,\frac{1.225043}{0.225043}=5.443595X\,\,\,\mathrm{and}\,X=735/5.443595=135.02. </math> {{soacopyright | 2023 }}")
ABy Admin
Nov 18'23
Exercise
Solution: A
The 3-year interest rate is [math]1.07^3-1=0.225043[/math]
Then,
[[math]]
735=X\ddot{a}_{\overline{\infty}|0.225043}=X\,\frac{1.225043}{0.225043}=5.443595X\,\,\,\mathrm{and}\,X=735/5.443595=135.02.
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.
ABy Admin
Nov 18'23
Solution: A
The 3-year interest rate is [math]1.07^3-1=0.225043[/math]
Then,
[[math]]
735=X\ddot{a}_{\overline{\infty}|0.225043}=X\,\frac{1.225043}{0.225043}=5.443595X\,\,\,\mathrm{and}\,X=735/5.443595=135.02.
[[/math]]
Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.