Revision as of 01:45, 15 June 2024 by Admin (Created page with "Using Stirling's Formula, prove that <math display="block"> {{2n}\choose n} \sim \frac {2^{2n}}{\sqrt {\pi n}}\ . </math>")
ABy Admin
Jun 15'24
Exercise
Using Stirling's Formula, prove that
[[math]]
{{2n}\choose n} \sim \frac {2^{2n}}{\sqrt {\pi n}}\ .
[[/math]]