Revision as of 16:59, 27 June 2024 by Admin (Created page with "'''Solution: C''' The number of defectives is approximately normal with mean 0.05 * 1900 = 95 and variance 90.25. Hence the probability of observing at least 115 defectives is approximately the probability that a standard normal exceeds (115-95)/9.5 = 2.105 which is approximately equal to 0.01765.")
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Exercise


ABy Admin
Jun 27'24

Answer

Solution: C

The number of defectives is approximately normal with mean 0.05 * 1900 = 95 and variance 90.25. Hence the probability of observing at least 115 defectives is approximately the probability that a standard normal exceeds (115-95)/9.5 = 2.105 which is approximately equal to 0.01765.

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