Revision as of 23:15, 2 November 2024 by Bot (Created page with "<div class="d-none"><math> \newcommand{\ex}[1]{\item } \newcommand{\sx}{\item} \newcommand{\x}{\sx} \newcommand{\sxlab}[1]{} \newcommand{\xlab}{\sxlab} \newcommand{\prov}[1] {\quad #1} \newcommand{\provx}[1] {\quad \mbox{#1}} \newcommand{\intext}[1]{\quad \mbox{#1} \quad} \newcommand{\R}{\mathrm{\bf R}} \newcommand{\Q}{\mathrm{\bf Q}} \newcommand{\Z}{\mathrm{\bf Z}} \newcommand{\C}{\mathrm{\bf C}} \newcommand{\dt}{\textbf} \newcommand{\goesto}{\rightarrow}...")
BBy Bot
Nov 03'24
Exercise
[math]
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[/math]
Perform each of the indicated operations and write the answer in the form [math]x + iy[/math].
- [math](3+i4)+(7-i3)[/math]
- [math](-2+i\sqrt2)+(-2-i\sqrt2)[/math]
- [math](-2+i\sqrt2)(-2-i\sqrt2)[/math]
- [math]\frac{3-i7}{2+i}[/math]
- [math](a+ib)(2a-i2b)[/math]
- [math]2(4-i3)+7(-2+i5)[/math]
- [math]\frac{-3+i4}{4-i3}[/math]
- [math]\frac{7+i}{-2-i5}[/math]
- [math]\frac{a+ib}{3a-i3b}[/math]
- [math]\frac{-2-i}{2-i}[/math]
- [math]\frac{25}{3-i4}[/math]
- [math](2+i7)(2-i5)[/math].