Revision as of 01:41, 3 May 2023 by Admin (Created page with "The annual profit of a life insurance company is normally distributed. The probability that the annual profit does not exceed 2000 is 0.7642. The probability that the annual...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
May 03'23

Exercise

The annual profit of a life insurance company is normally distributed.

The probability that the annual profit does not exceed 2000 is 0.7642. The probability that the annual profit does not exceed 3000 is 0.9066.

Calculate the probability that the annual profit does not exceed 1000.

  • 0.1424
  • 0.3022
  • 0.5478
  • 0.6218
  • 0.7257

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 03'23

Solution: C

[[math]] \begin{align*} \operatorname{P}(Z \leq 0.72) = 0.7642 = \operatorname{P}(X \leq 2000 ) = \operatorname{P}[Z \leq (2000-\mu)/\sigma] \\ 0.72 = (2000-\mu)/\sigma \\ \operatorname{P}( Z ≤ 1.32) = 0.9066 = \operatorname{P}( X ≤ 3000) = \operatorname{P}[ Z ≤ (3000 − µ ) / σ ] \\ 1.32 = (3000 − \mu ) / \sigma \\ 1.32 / 0.72 = (3000 − \mu ) / (2000 − \mu ) \\ 1.8333(2000 − \mu )= 3000 − \mu \\ \mu =[1.8333(2000) − 3000] / (1.8333 − 1) = 800 \\ \sigma =(3000 − \mu ) /1.32 = 1666.67 \\ \operatorname{P}( X ≤ 1000) = \operatorname{P}[ Z ≤ (1000 − 800) /1666.67] = \operatorname{P}( Z ≤ 0.12) = 0.5478. \end{align*} [[/math]]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

00