Revision as of 21:26, 3 May 2023 by Admin (Created page with "An actuary has discovered that policyholders are three times as likely to file two claims as to file four claims. The number of claims filed has a Poisson distribution. Calcu...")
May 03'23
Exercise
An actuary has discovered that policyholders are three times as likely to file two claims as to file four claims. The number of claims filed has a Poisson distribution.
Calculate the variance of the number of claims filed.
- [math]\frac{1}{\sqrt{3}}[/math]
- 1
- [math]\sqrt{2}[/math]
- 2
- 4
May 03'23
Solution: D
Let [math]N[/math] be the number of claims filed. We are given
[[math]]
P[N = 2] = \frac{e^{-\lambda}\lambda^2}{2!} = 3 \frac{e^{-\lambda}\lambda^4}{4!} = 3 \cdot P[N=4] 24 \lambda^2 = 6 \lambda^4
[[/math]]
which implies that [math]\lambda = 2 [/math]. Therefore, [math]\operatorname{Var}[N] = \lambda = 2 [/math].