Revision as of 21:41, 3 May 2023 by Admin (Created page with "An insurance company issues 1250 vision care insurance policies. The number of claims filed by a policyholder under a vision care insurance policy during one year is a Poisson...")
ABy Admin
May 03'23
Exercise
An insurance company issues 1250 vision care insurance policies. The number of claims filed by a policyholder under a vision care insurance policy during one year is a Poisson random variable with mean 2. Assume the numbers of claims filed by different policyholders are mutually independent.
Calculate the approximate probability that there is a total of between 2450 and 2600 claims during a one-year period?
- 0.68
- 0.82
- 0.87
- 0.95
- 1.00
ABy Admin
May 03'23
Solution: E
The tour operator collects 21 x 50 = 1050 for the 21 tickets sold. The probability that all 21 passengers will show up is
(1 − 0.02 )21 = (0.98)21 = 0.65.
Therefore, the tour operator’s expected revenue is
1050 – 100(065) = 985.