Revision as of 22:01, 3 May 2023 by Admin (Created page with "'''Solution: A''' The number of components that fail has a binomial(2, 0.05) distribution. Then, <math display = "block"> \operatorname{P}( N ≥ 2)= p(2) + p(3) = \binom{3}...")
Exercise
ABy Admin
May 03'23
Answer
Solution: A
The number of components that fail has a binomial(2, 0.05) distribution. Then,
[[math]]
\operatorname{P}( N ≥ 2)= p(2) + p(3) = \binom{3}{2}(0.05)^2(0.95) + \binom{3}{3}(0.05)^3 = 0.00725.
[[/math]]
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