Revision as of 13:55, 6 May 2023 by Admin (Created page with "'''Solution: D''' Var(Z) = Var(3X + 2Y – 5) = 9Var(X) + 4Var(Y) = 9(3) + 4(4) = 43. {{soacopyright | 2023 }}")
Exercise
ABy Admin
May 06'23
Points scored by a game participant can be modeled by [math]Z = 3X + 2Y – 5[/math]. [math]X[/math] and [math]Y[/math] are independent random variables with [math]\operatorname{Var} (X) = 3[/math] and [math]\operatorname{Var} (Y) = 4[/math].
Calculate [math]\operatorname{Var}(Z) [/math].