Revision as of 23:15, 7 May 2023 by Admin (Created page with "'''Solution: B''' The sum of independent Poisson variables is also Poisson, with the means added. Thus the number of tornadoes in a three week period is Poisson with a mean o...")
Exercise
ABy Admin
May 08'23
Answer
Solution: B
The sum of independent Poisson variables is also Poisson, with the means added. Thus the number of tornadoes in a three week period is Poisson with a mean of 3x2 = 6. Then,
[[math]]
P( N \lt 4) = p(0) + p(1) + p(2) + p(3) = e^{-6}\left( \frac{6^0}{0!} + \frac{6^1}{1!} + \frac{6^2}{2!} + \frac{6^3}{3!} + \right) = 0.1512.
[[/math]]