Revision as of 13:04, 14 May 2023 by Admin (Created page with "For a collective risk model the number of losses, N, has a Poisson distribution with <math>\lambda = 20</math>. The common distribution of the individual losses has the follow...")
ABy Admin
May 14'23
Exercise
For a collective risk model the number of losses, N, has a Poisson distribution with [math]\lambda = 20[/math]. The common distribution of the individual losses has the following characteristics:
- [math]\operatorname{E}[ X ] = 70 [/math]
- [math]\operatorname{E}[ X \wedge 30] = 25 [/math]
- [math]\operatorname{Pr}( X \gt 30) = 0.75 [/math]
- [math]\operatorname{E}[ X^2 | X \gt 30] = 9000 [/math]
An insurance covers aggregate losses subject to an ordinary deductible of 30 per loss.
Calculate the variance of the aggregate payments of the insurance.
- 54,000
- 67,500
- 81,000
- 94,500
- 108,000
ABy Admin
May 14'23
Key: B
Losses in excess of the deductible occur at a Poisson rate of [math]\lambda^* = [1 − F (30)]\lambda = 0.75(20) = 15.[/math] The expected payment squared per payment is
[[math]]
\begin{aligned}
&\operatorname{E}[( X − 30)^2 | X \gt 30) = \operatorname{E}[ X^2 − 60 X + 900 | X \gt 30) \\
&\operatorname{E}[ X^2 − 60( X − 30) − 900 | X \gt 30] \\
&=9000-60 \frac{70-25}{0.75} - 900 = 4500.
\end{aligned}
[[/math]]
The variance of S is the expected number of payments times the second moment, 15(4500) =67,500.