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May 14'23
Exercise
You are given:
- A sample of losses is: 600 700 900
- No information is available about losses of 500 or less.
- Losses are assumed to follow an exponential distribution with mean [math]\theta [/math].
Calculate the maximum likelihood estimate of [math]\theta[/math]
- 233
- 400
- 500
- 733
- 1233
May 14'23
Key: A
These observations are truncated at 500. The contribution to the likelihood function is
[[math]]
\frac{f(x)}{1-F(500)} = \frac{\theta^{-1}e^{-x/\theta}}{e^{-500/\theta}}.
[[/math]]
Then the likelihood function is
[[math]]
\begin{aligned}
&L(\theta) = \frac{\theta^{-1}e^{-600/\theta}\theta^{-1}e^{-700/\theta}\theta^{-1}e^{-900/\theta}}{\left( e^{-500/\theta}\right)^3} = \theta^{-3}e^{-700/\theta} \\
& l (\theta ) = \ln L(\theta ) = −3\ln \theta − 700\theta^{−1} \\
& l^{'}(\theta) = -3\theta^{-1} + 700\theta^{-2} = 0 \\
& \theta = 700 / 3 = 233.33.
\end{aligned}
[[/math]]