Revision as of 16:19, 26 May 2023 by Admin (Created page with "'''Key: C''' Even though the formula for R<sup>2</sup> involves RSS and TSS, she just needs their ratio, which can be obtained from F. <math display = "block"> \begin{aligne...")
Exercise
May 26'23
Answer
Key: C
Even though the formula for R2 involves RSS and TSS, she just needs their ratio, which can be obtained from F.
[[math]]
\begin{aligned}
F &= \frac{(TSS − RSS ) / 4}{RSS / (105 − 4 − 1)} = 20 \\
\frac{TSS-RSS}{RSS} &= 20(4)/100 = 0.80 \\
\frac{TSS}{RSS} &= 1.80 \\
\frac{RSS}{TSS} &= \frac{1}{1.80} \\
R^2 &= 1- \frac{RSS}{TSS} \\
&= 1- \frac{1}{1.80}\\
&= \frac{0.80}{1.80} \\
&= 0.44
\end{aligned}
[[/math]]