Revision as of 16:51, 26 May 2023 by Admin (Created page with "'''Key: B''' <math>c= y_t − y_{t−1}</math> and hence <math>c_1, c_2 ,\ldots c_{10} = 2,3,5,3,5, 2, 4,1, 2,3.</math> The mean of the <math>c</math> values is 3, the varia...")
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Exercise


ABy Admin
May 26'23

Answer

Key: B

[math]c= y_t − y_{t−1}[/math] and hence [math]c_1, c_2 ,\ldots c_{10} = 2,3,5,3,5, 2, 4,1, 2,3.[/math]

The mean of the [math]c[/math] values is 3, the variance is (1+0+4+0+4+1+1+4+1+0)/9 = 16/9. The standard deviation is 4/3. The standard error of the forecast is [math](4/3)\sqrt{9} = 4. [/math]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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