Revision as of 00:55, 18 November 2023 by Admin (Created page with "'''Solution: C''' <math display = "block"> \begin{aligned} & 500(1+X)^2=600 \\ & X=0.095445 \\ & 100(1+Y)^2+100(1+Y)=Z \\ & 600(1.10)^2+100(1.10)=600+Z \\ & Z=236 \\ & 100(1+Y)^2+100(1+Y)=236 \\ & (1+Y)^2+(1+Y)-2.36=0 \\ & (1+Y)=\frac{-1 \pm \sqrt{1+9.44}}{2} \\ & Y=0.115549 \\ & Y-X=0.0201\end{aligned} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{aligned} & 500(1+X)^2=600 \\ & X=0.095445 \\ & 100(1+Y)^2+100(1+Y)=Z \\ & 600(1.10)^2+100(1.10)=600+Z \\ & Z=236 \\ & 100(1+Y)^2+100(1+Y)=236 \\ & (1+Y)^2+(1+Y)-2.36=0 \\ & (1+Y)=\frac{-1 \pm \sqrt{1+9.44}}{2} \\ & Y=0.115549 \\ & Y-X=0.0201\end{aligned}
[[/math]]
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