Revision as of 10:41, 18 November 2023 by Admin (Created page with "Which of the following is an expression for the present value of a perpetuity with annual payments of 1, 2, 3, ..., where the first payment will be made at the end of n years, using an annual effective interest rate of i? <ul class="mw-excansopts"> <li><math display = "block">\frac{\ddot{a}_{\overline{n}|}-nv^n}{i}</math></li> <li><math display = "block">\frac{n-a_{\overline{n}|}}{i}</math></li> <li><math display = "block">\frac{v^n}{d}</math></li> <li><math display = "...")
ABy Admin
Nov 18'23
Exercise
Which of the following is an expression for the present value of a perpetuity with annual payments of 1, 2, 3, ..., where the first payment will be made at the end of n years, using an annual effective interest rate of i?
- [[math]]\frac{\ddot{a}_{\overline{n}|}-nv^n}{i}[[/math]]
- [[math]]\frac{n-a_{\overline{n}|}}{i}[[/math]]
- [[math]]\frac{v^n}{d}[[/math]]
- [[math]]\frac{v^n}{d^2}[[/math]]
- [[math]]\frac{v^n}{di}[[/math]]
ABy Admin
Nov 18'23
Solution: D
One way to view these payments is as a sequence of level immediate perpetuities of 1 that are deferred n-1, n, n+1,... years. The present value is then
[[math]]
v^{n-1}/\,i+ v^{n}\ /\,i+ v^{n+1}/i+\cdots=\left( v^{n-2}/i\,\right)\left( v+ v^{2}+ v^{3}+\cdots\right)= v^{n-2}/i^2.
[[/math]]
Noting that only answers C, D, and E have this form and all have the same numerator,
[[math]]
v^{n-2}/i^2\ = \, v^{n}/(vi)^{2}\,=\, v^{n}\,/\,d^2.
[[/math]]