Revision as of 11:48, 18 November 2023 by Admin (Created page with "'''Solution: D''' With a continuously compounded annual interest rate of 6%, The value of the first annuity is <math display = "block"> 600.000=X(I\ddot{a})_{\overline{{{20}}|}}=X\frac{\ddot{a}_{\overline{20}|}-20v^{20}}{d}=X\,{\frac{{\frac{1-e^{-0.2}}{1-e^{-0.06}}}-20e^{-1.2}}{1-e^{-0.06}}}=102.614X. </math> Hence, X = 600,000/102.614 = 5847.155. Then the value of the second annuity is <math display = "block"> 5847.155{\frac{\ddot{a}_{\overline{25}|}-25\nu^{25}}{d...")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: D
With a continuously compounded annual interest rate of 6%,
The value of the first annuity is
[[math]]
600.000=X(I\ddot{a})_{\overline{{{20}}|}}=X\frac{\ddot{a}_{\overline{20}|}-20v^{20}}{d}=X\,{\frac{{\frac{1-e^{-0.2}}{1-e^{-0.06}}}-20e^{-1.2}}{1-e^{-0.06}}}=102.614X.
[[/math]]
Hence, X = 600,000/102.614 = 5847.155. Then the value of the second annuity is
[[math]]
5847.155{\frac{\ddot{a}_{\overline{25}|}-25\nu^{25}}{d}}=5847.155{\frac{\frac{1-e^{-0.5}}{1-e^{-0.06}}-25e^{-1.5}}{1-e^{-0.06}}}=779.366.
[[/math]]