Revision as of 11:56, 18 November 2023 by Admin (Created page with "'''Solution: B''' <math display = "block"> \begin{aligned} 2600=P a_{\overline{\infty}|0.06}+v9(I a)_{\overline{\infty}|0.06} \\ =P{\frac{1}{0.06}}+{\frac{1}{1.06}}9{\frac{1.06}{0.06^{2}}} \\ {\frac{P}{0.06}}+2500 \\ P = (2600-2500)(0.06) =6 \end{aligned} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: B
[[math]]
\begin{aligned}
2600=P a_{\overline{\infty}|0.06}+v9(I a)_{\overline{\infty}|0.06} \\
=P{\frac{1}{0.06}}+{\frac{1}{1.06}}9{\frac{1.06}{0.06^{2}}} \\
{\frac{P}{0.06}}+2500 \\
P = (2600-2500)(0.06) =6
\end{aligned}
[[/math]]
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