Revision as of 12:03, 18 November 2023 by Admin (Created page with "'''Solution: B''' The accumulation is <math display = "block"> 10X+0.12X(Is)_{\overline{10}|0.08}=10X+0.12X{\frac{\ddot{s}_{\overline{10}|0.08}-10}{0.08}}=10X+0.12X{\frac{15.6455-10}{0.08}}=18.4683X </math> Then, X = 10,000/18.4683 = 541.47 {{soacopyright | 2023 }}")
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Exercise

ABy Admin
Nov 18'23

Answer

Solution: B

The accumulation is

[[math]] 10X+0.12X(Is)_{\overline{10}|0.08}=10X+0.12X{\frac{\ddot{s}_{\overline{10}|0.08}-10}{0.08}}=10X+0.12X{\frac{15.6455-10}{0.08}}=18.4683X [[/math]]

Then, X = 10,000/18.4683 = 541.47

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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