Revision as of 19:37, 18 November 2023 by Admin (Created page with "'''Solution: C''' <math display = "block"> \begin{aligned} 2000 & =X(1.08)^{14}+X(1.03)(1.08)^{13}+X(1.03)^2(1.08)^{12}+\cdots+X(1.03)^{14} \\ & =X \frac{1.08^{14}-1.03^{15} / 1.08}{1-1.03 / 1.08} \\ & =32.284 X \\ X & =61.95\end{aligned} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{aligned} 2000 & =X(1.08)^{14}+X(1.03)(1.08)^{13}+X(1.03)^2(1.08)^{12}+\cdots+X(1.03)^{14} \\ & =X \frac{1.08^{14}-1.03^{15} / 1.08}{1-1.03 / 1.08} \\ & =32.284 X \\ X & =61.95\end{aligned}
[[/math]]
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