Revision as of 21:53, 18 November 2023 by Admin (Created page with "'''Solution: B''' Option 1: <math>2000 = P a_{\overline{10}|0.0807}</math> Option 2: Interest needs to be 2990-2000=990 <math display = "block"> \begin{array}{l}{{990=i[2000+1800+1600+\dots+200]}}\\ {{=11,000i}}\\ {{i=0.09=9.00\%}}\end{array} </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: B
Option 1: [math]2000 = P a_{\overline{10}|0.0807}[/math]
Option 2: Interest needs to be 2990-2000=990
[[math]]
\begin{array}{l}{{990=i[2000+1800+1600+\dots+200]}}\\ {{=11,000i}}\\ {{i=0.09=9.00\%}}\end{array}
[[/math]]
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