Revision as of 23:33, 18 November 2023 by Admin (Created page with "'''Solution: D''' The effective annual interest rate is <math display = "block">\dot{l}=(1-d)^{-1}-1=(1-0.055)^{-1}-1=5.829 \%. </math> The balance on the loan at time 2 is 15, 000, 000(1.0582)<sup>2</sup> =16, 796,809. The number of payments is given by <math display = "block">1,200,000 a_{\overline{n}|} = 16, 796,809</math> which gives <math>n = 29.795 \Rightarrow 29</math> payments of 1,200,000. The final equation of value is <math display = "block"> \begin{align...")
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Exercise


ABy Admin
Nov 18'23

Answer

Solution: D

The effective annual interest rate is

[[math]]\dot{l}=(1-d)^{-1}-1=(1-0.055)^{-1}-1=5.829 \%. [[/math]]

The balance on the loan at time 2 is 15, 000, 000(1.0582)2 =16, 796,809.

The number of payments is given by

[[math]]1,200,000 a_{\overline{n}|} = 16, 796,809[[/math]]

which gives [math]n = 29.795 \Rightarrow 29[/math]

payments of 1,200,000. The final equation of value is

[[math]] \begin{align*} 1.200,000a_{\overline{{{29}}}|}+X(1.0582)^{-30}=16,796,809 \\ X=(16,796,809-16,621,012)(5.45799)=959,490. \end{align*} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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