Revision as of 23:33, 18 November 2023 by Admin (Created page with "'''Solution: D''' The effective annual interest rate is <math display = "block">\dot{l}=(1-d)^{-1}-1=(1-0.055)^{-1}-1=5.829 \%. </math> The balance on the loan at time 2 is 15, 000, 000(1.0582)<sup>2</sup> =16, 796,809. The number of payments is given by <math display = "block">1,200,000 a_{\overline{n}|} = 16, 796,809</math> which gives <math>n = 29.795 \Rightarrow 29</math> payments of 1,200,000. The final equation of value is <math display = "block"> \begin{align...")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: D
The effective annual interest rate is
[[math]]\dot{l}=(1-d)^{-1}-1=(1-0.055)^{-1}-1=5.829 \%.
[[/math]]
The balance on the loan at time 2 is 15, 000, 000(1.0582)2 =16, 796,809.
The number of payments is given by
[[math]]1,200,000 a_{\overline{n}|} = 16, 796,809[[/math]]
which gives [math]n = 29.795 \Rightarrow 29[/math]
payments of 1,200,000. The final equation of value is
[[math]]
\begin{align*}
1.200,000a_{\overline{{{29}}}|}+X(1.0582)^{-30}=16,796,809 \\
X=(16,796,809-16,621,012)(5.45799)=959,490.
\end{align*}
[[/math]]