Revision as of 23:42, 18 November 2023 by Admin (Created page with "'''Solution: B''' The monthly interest rate is <math display = "block"> j = (1.08)^{1/12}-1 = 0.643\%. </math> Then, <math display = "block"> 20.000S_{\overline{3}|0.08}=X \ddot{s}_{\overline{252}|0.00643}\quad90,122.24=630.99X,\quad X=142.83. </math> {{soacopyright | 2023 }}")
Exercise
ABy Admin
Nov 18'23
Answer
Solution: B
The monthly interest rate is
[[math]]
j = (1.08)^{1/12}-1 = 0.643\%.
[[/math]]
Then,
[[math]]
20.000S_{\overline{3}|0.08}=X \ddot{s}_{\overline{252}|0.00643}\quad90,122.24=630.99X,\quad X=142.83.
[[/math]]
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