Revision as of 00:56, 19 November 2023 by Admin (Created page with "'''Solution: C''' <math display = "block"> \begin{array}{l} {{\mathrm{Int}_{11} = i \cdot [ 900 \cdot a_{\overline{20}|i} + 300a_{\overline{10}|i}] =900(1-{ v}^{20})+300(1-{ v}^{10})=1200-300{ v}^{10}-900{ v}^{20}}} \\ {{\displaystyle{\mathrm{Int}_{21}=i\left[900\cdot a_{\overline{{{10}}}|i}\right]=900(1- v^{{\mathrm{i0}}})}}}\\ {{\displaystyle{\mathrm{Int}_{11=}2\mathrm{Int}_{21}\displaystyle\Rightarrow1200-300 v^{{\mathrm{i0}}}-900 v^{{\mathrm{i0}}}=1800-1800 v^{{\ma...")
Exercise
ABy Admin
Nov 19'23
Answer
Solution: C
[[math]]
\begin{array}{l}
{{\mathrm{Int}_{11} = i \cdot [ 900 \cdot a_{\overline{20}|i} + 300a_{\overline{10}|i}] =900(1-{ v}^{20})+300(1-{ v}^{10})=1200-300{ v}^{10}-900{ v}^{20}}} \\
{{\displaystyle{\mathrm{Int}_{21}=i\left[900\cdot a_{\overline{{{10}}}|i}\right]=900(1- v^{{\mathrm{i0}}})}}}\\ {{\displaystyle{\mathrm{Int}_{11=}2\mathrm{Int}_{21}\displaystyle\Rightarrow1200-300 v^{{\mathrm{i0}}}-900 v^{{\mathrm{i0}}}=1800-1800 v^{{\mathrm{i0}}}}=1800-1800 v^{{\mathrm{i0}}}}}\\ {{\displaystyle{\mathrm{Int}}_{21}=900(1- v^{10})=300}}\end{array}
[[/math]]
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